Breeding Question

[Liriel Garnet]

OK, here comes some fun LOL.

parents = shown/hidden
mom = E&I/OciLav+ OdyK/BlushQ+
dad = E&I/P&W?+ Purple Rain/OdyK or BlushQ+

TWO cases for the furs (since there is overlap between E&I and P&W in what has been proven):

First, IF P&W is recessive to E&I, then:

box furs: 1/3 E&I/E&I 1/3 E&I/P&W+ 1/3 E&I/OciLav+
so technically chances are 1/3 to hide E&I, 1/6 to hide P&W, 1/6 to hide whatever the P&W hid (which may also be P&W), 1/6 to hide Oci Lav, 1/6 to hide whatever the Lav hid (which may also be Lav)

furs likelihood to be hidden:
E&I (1/3 chance)
P&W/Oci Lav (equal at 1/6 each)
two unknowns (equal at 1/6 each)
Chat Cream & White 1 is most dominant that's recessive to all listed.

Second, if P&W is NOT recessive to E&I, then the only change is that dad's hidden MUST be what hid behind the P&W (which by definition means it cannot be more P&W since if it was dominant it would show), which changes the odds to:
1/3 to hide E&I, 1/3 to hide whatever the P&W hid, 1/6 to hide Oci Lav, 1/6 to hide whatever the Lav hid

furs likelihood to be hidden:
E&I/unknown hidden from behind the P&W (equal at 1/3 each)
Oci Lav/unknown hidden from behind the Oci Lav (equal at 1/6 each)
Chat Cream & White 1 is still the most dominant that's recessive to all listed.


Eyes:
Ody K/BlushQuartz+ (one for sure hides, equal chances for each)
which means technically, the chances are:
1/2 OdyK
1/4 Blush Quartz
1/4 Whatever is hidden behind the Blush Quartz (which may be more Blush Quartz)
the others on the list are not even in the running for the hidden.
Ody Bellini is the only eye known recessive to Blush Quartz, therefore it is the most dominant that's recessive to all listed.